Convert picojoule/second to foot pound-force/hour
Please provide values below to convert picojoule/second [pJ/s] to foot pound-force/hour [ft*lbf/h], or Convert foot pound-force/hour to picojoule/second.
How to Convert Picojoule/second to Foot Pound-Force/hour
1 pJ/s = 2.65522441956794e-09 ft*lbf/h
Example: convert 15 pJ/s to ft*lbf/h:
15 pJ/s = 15 × 2.65522441956794e-09 ft*lbf/h = 3.98283662935191e-08 ft*lbf/h
Picojoule/second to Foot Pound-Force/hour Conversion Table
| picojoule/second | foot pound-force/hour |
|---|
Picojoule/second
A picojoule per second (pJ/s) is a unit of power equivalent to one trillionth of a joule per second, representing an extremely small rate of energy transfer.
History/Origin
The picojoule per second is derived from the SI units of energy (joule) and time (second), with 'pico' denoting a factor of 10^-12. It has been used in scientific contexts requiring precise measurement of very small power levels, especially in fields like nanotechnology and low-power electronics.
Current Use
This unit is used in scientific and engineering applications to quantify extremely low power levels, such as in nanotechnology, bioelectronics, and other fields where minute energy transfer rates are relevant.
Foot Pound-Force/hour
Foot pound-force per hour (ft*lbf/h) is a unit of power representing the amount of work done in foot-pounds over the period of one hour.
History/Origin
The foot pound-force is an imperial unit of work or energy, and its use in power measurements like ft*lbf/h has been common in engineering fields in the United States. It has been used historically in mechanical and thermodynamic contexts before the adoption of SI units.
Current Use
Today, ft*lbf/h is primarily used in specific engineering applications, such as in the measurement of small power outputs in mechanical systems, though it is largely replaced by SI units like watts in most scientific and international contexts.