Convert decijoule/second to pound-foot/hour
Please provide values below to convert decijoule/second [dJ/s] to pound-foot/hour [lbf*ft/h], or Convert pound-foot/hour to decijoule/second.
How to Convert Decijoule/second to Pound-Foot/hour
1 dJ/s = 265.522441956794 lbf*ft/h
Example: convert 15 dJ/s to lbf*ft/h:
15 dJ/s = 15 × 265.522441956794 lbf*ft/h = 3982.83662935191 lbf*ft/h
Decijoule/second to Pound-Foot/hour Conversion Table
| decijoule/second | pound-foot/hour |
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Decijoule/second
A decijoule per second (dJ/s) is a unit of power equivalent to one-tenth of a joule per second, representing the rate of energy transfer or conversion.
History/Origin
The decijoule is a decimal submultiple of the joule, introduced as part of the metric system to facilitate measurements at smaller scales. Its usage in power calculations, such as decijoules per second, has been consistent with the adoption of SI units, though it is less common in modern practice.
Current Use
Decijoule per second is rarely used in contemporary contexts; power is more commonly expressed in watts (joules per second). When used, it typically appears in specialized scientific or engineering applications requiring fine-grained energy rate measurements at the deci level.
Pound-Foot/hour
Pound-foot per hour (lbf·ft/h) is a unit of power representing the amount of work done in foot-pounds per hour, commonly used in engineering to measure power output or consumption.
History/Origin
The pound-foot per hour originated from the imperial system of units, primarily used in the United States, to quantify power in mechanical and engineering contexts. Its usage has declined with the adoption of SI units but remains relevant in certain industries.
Current Use
Today, pound-foot per hour is primarily used in specific engineering fields, such as mechanical and aerospace engineering, for measuring power in systems where imperial units are standard. It is also used in historical data and legacy systems.